python剪刀石头布游戏功能：玩家选择 剪刀 石头 布 其中一项，电脑随机出拳。根据我们平时的规则，程序进行输赢的判定。下面我们一起来看下如何实现工具/原料more电脑Python开发工具方法/步骤1/8分步阅读

由于需要电脑随机出拳，所以我们这里导入随机数模块，具体代码：

import random

然后用input 代码和用户交互，让用户选择出 剪刀 石头或者布

player = input(请输入要出的选项:剪刀(1)/石头(2)/布(3))

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对玩家出拳进行判断，我们这里用 1 代表了 剪刀 2 代表石头 3 代表布 所以我们限制玩家只能出 这三个数字，输入其他字符 则提示玩家出拳错误

if player.isdigit() and int(player) = 1 and int(player) = 3:

else: print(出拳有误)

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下面在用户输入正确的情况下 写入判断代码，首先把用户输入的数字转换成整数类型，以及将电脑随机数代码完善

player = int(player)cpu = random.randint(1, 3)

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继续用if判断，将电脑和用户输入的数字判断成拳头，代码如下：

if player == 1: player1 = 剪刀if player == 2: player1 = 石头if player == 3: player1 = 布if cpu == 1: cpu1 = 剪刀if cpu == 2: cpu1 = 石头if cpu == 3: cpu1 = 布print(玩家出拳为:, player1, 电脑出拳为:, cpu1)

判断最后打印出双方出拳的结果

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然后我们进行胜负条件的判断，我们先写上当用户胜利时候的情况，具体代码如下：

if (player == 1 and cpu == 3) \ or (player == 2 and cpu == 1) \ or (player == 3 and cpu == 2): print(玩家胜利)

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按照同样的判断方法，判断出电脑胜利和平局的结果：

if (player == 1 and cpu == 2) \ or (player == 2 and cpu == 3) \ or (player == 3 and cpu == 1): print(电脑胜利)if (player == 1 and cpu == 1) \ or (player == 2 and cpu == 2) \ or (player == 3 and cpu == 3): print(平局)

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经过以上代码，我们基本完成了整个游戏的过程，下面运行一下看效果：

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整体代码总结：

import randomplayer = input(请输入要出的选项:剪刀(1)/石头(2)/布(3))if player.isdigit() and int(player) = 1 and int(player) = 3: player = int(player) cpu = random.randint(1, 3) if player == 1: player1 = 剪刀 if player == 2: player1 = 石头 if player == 3: player1 = 布 if cpu == 1: cpu1 = 剪刀 if cpu == 2: cpu1 = 石头 if cpu == 3: cpu1 = 布 print(玩家出拳为:, player1, 电脑出拳为:, cpu1)# if (player == 1 and cpu == 3) \ or (player == 2 and cpu == 1) \ or (player == 3 and cpu == 2): print(玩家胜利) if (player == 1 and cpu == 2) \ or (player == 2 and cpu == 3) \ or (player == 3 and cpu == 1): print(电脑胜利) if (player == 1 and cpu == 1) \ or (player == 2 and cpu == 2) \ or (player == 3 and cpu == 3): print(平局)else: print(出拳有误)

注意事项

Python中所有字符需要是英文格式

if循环中注意tab缩进问题

PYTHON基础PYTHON游戏项目