sql中怎样把同一张表中相同字段的内容合并为一条记录?并统计数量
来源:网络收集 点击: 时间:2024-02-2712SELECT Customer_ID,Customer_Name,a href=https://www.baidu.com/s?
wd=STUFFtn=44039180_cprfenlei=mv6quAkxTZn0IZRqIHckPjm4nH00T1Y3ujRkn1R1uW9hryN-
njF90ZwV5Hcvrjm3rH6sPfKWUMw85HfYnjn4nH6sgvPsT6KdThsqpZwYTjCEQLGCpyw9Uz4Bmy-bIi4WUvYETgN-TLwGUv3EnHm1rH04rH6snjnkn1mYnjR3n0 target=_blank
class=baidu-highlightSTUFF/a((SELECT ,+Linkman_Name FROM Linkman WHERE Customer_ID=Customer.Customer_ID FOR XML a href=
https://www.baidu.com/s?wd=PATHtn=44039180_cprfenlei=mv6quAkxTZn0IZRqIHckPjm4nH00T1Y3ujRkn1R1uW9hryN-
njF90ZwV5Hcvrjm3rH6sPfKWUMw85HfYnjn4nH6sgvPsT6KdThsqpZwYTjCEQLGCpyw9Uz4Bmy-bIi4WUvYETgN-TLwGUv3EnHm1rH04rH6snjnkn1mYnjR3n0 target=_blank
class=baidu-highlightPATH/a()),1,1,) Linkman_Name FROM Customer
把表名tt换下就可以了购买产品id是字符串类型的话用这个select a.客户id,stuff((select ,+购买产品id from tt b wherea.客户id=b.客户id for XML path() ),1,1,) gg from tt a group by a.客户id
如果购买产品id是整型的话,用这个select a.客户id,stuff((select ,+cast(购买产品id as nvarchar(max)) from tt b wherea.客户id=b.客户id for XML path() ),1,1,) gg from tt a group by a.客户id
参考资料;百度百科-sql
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