订阅Latex公式环境中如何对齐公式？
来源：网络收集 点击： 时间：2024-05-03\documentclass{report}
\usepackage{amsmath}
\usepackage{stackengine}
tackMath
etstackgap{L}{1.2\normalbaselineskip}
\begin{document}
\begin{align}
a+b+c+d+e+f = 15000 \text{for } a = 1 ... 15 \\
D_t= \left\{\Centerstack{\text{equation} ,\\
\text{another equation}}\right. \Centerstack{ \text{for } t = 1 ... 10 \\ \text{for } t = 1 ... 10}
\end{align}
\end{document}
程序编译代码如下图
方法21/1\documentclass{article}
\usepackage{mathtools}
\begin{document}
\begin{alignat}{2}
a+b+c+d+e+f = 15000
\quad \text{for } a = 1 ... 15 \\
D_t=\begin{cases} \text{equation} , \\ \text{another equation} ,\end{cases}
\begin{aligned} \text{for } t = 1 ... 10 \\
\text{for } t = 1 ... 10
\end{aligned}
\end{alignat}
\end{document}
程序编译代码如下图
方法31/1\documentclass{article}
\usepackage{mathtools}
\begin{document}
\begin{alignat}{2}
a+b+c+d+e+f = 15000
\quad \text{for } a = 1 ... 15 \\
D_t= \mathrlap{\begin{cases} \text{equation} , \text{for } t = 1 ... 10 \\
\text{another equation} ,\hspace{1.9em}
\text{for }t = 1 ... 10
\end{cases}}
\end{alignat}
\end{document}
程序编译代码如下图
方法41/1\begin{equation}\label{eq:02}
%\begin{aligned}
d_{ek}=\left\{\begin{array}{ll}
qrt{(\bar{x}_{k1}-\bar{x}_{e})^2+(\bar{y}_{k1}-\bar{y}_{e})^2} {\rm if} \, \bar{x}_{e}\bar{x}_{k1}\\
\frac{\left \| \textbf{A}_{ek} \right \|}{l_k} {\rm if} \,
\bar{x}_{k1} \leq\bar{x}_{e} \leq \bar{x}_{k2} \\
qrt{(\bar{x}_{k2}-\bar{x}_{e})^2+(\bar{y}_{k2}-\bar{y}_{e})^2} {\rm if} \,
\bar{x}_{e} \bar{x}_{k2}
\end{array}\right.
%\end{aligned}
\end{equation}
程序编译代码如下图
方法51/1\begin{equation}\label{eq:05}
%\begin{aligned}
\left\{\begin{array}{ll}
\phi(\textbf{x})0 {\rm if} \, \textbf{x} \in (D \backslash \Omega)\\
\phi(\textbf{x})= 0 {\rm if} \, \textbf{x} \in (\partial \Omega \cap D) \\
\phi(\textbf{x}) 0 {\rm if} \, \textbf{x} \in (\Omega \backslash \partial \Omega)
\end{array}\right.
%\end{aligned}
\end{equation}
程序编译代码如下图
方法61/1\documentclass{article}
\usepackage{amsmath}
\begin{document}
\[ \begin{cases}
W_n(\mathcal{O}_k) = \bigl\{ X^{(n)}= (x_0, x_1, \dotsc, x_{n-1}) \in
W_n(k) \mid x_i \in \mathcal{O}_k,\ 0 \le i \le n-1 \bigl\}\\
W_n(m_k) = \bigl\{ X^{(n)}= (x_0, x_1, \dotsc, x_{n-1}) \in
W_n(k) \mid x_i\in m_k,\ 0 \le i \le n-1 \bigl\}\\
W_n(m_k)^{(m)} = \bigl\{ X^{(n)} = (x_0, x_1, \dotsc, x_{n-1}) \in
W_n(k) \mid {}\\ \hfill v(x_i)\geq m/p^{n-1-i},\ 0 \le i\le n-1 \bigl\}
\end{cases}\]
\end{document}
程序编译代码如下图
方法71/1\documentclass{article}
\usepackage{inputenc}
\usepackage{fontenc}
\usepackage{empheq}
\begin{document}
\[
\begin{cases}
W_n(\mathcal{O}_k) =\bigl\{X^{(n)}=(x_0,x_1,\cdots,x_{n-1})\in
W_n(k): x_i\in \mathcal{O}_k,\text{ } i\in \{0,1,\cdots, n-1\}\bigr \}\\
W_n(m_k)=\bigl\{X^{(n)}=(x_0,x_1,\cdots,x_{n-1})\in W_n(k) :x_i\in m_k,\text{ } i\in \{0,1,\cdots, n-1\} \bigr\} \\
W_n(m_k)^{(m)}= \biggl\{X^{(n)}=(x_0,x_1,\cdots,x_{n-1})\in
W_n(k): \:\Bigm\vert
\begin{matrix*}v(x_i)\geq m/p^{n-1-i},\text{ }\\ i\in\{0,1,\cdots, n-1\}\end{matrix*}\biggr \}
\end{cases}
\]
\end{document}
程序编译代码如下图
方法81/1\documentclass{article}
\usepackage{inputenc}
\usepackage{fontenc}
\usepackage{empheq}
\begin{document}
\begin{empheq}
{align*}
W_n(\mathcal{O}_k) =\bigl\{X^{(n)}=(x_0,x_1,\cdots,x_{n-1})\in W_n(k): x_i\in \mathcal{O}_k \}\bigr \}\\
W_n(m_k)=\bigl\{X^{(n)}=(x_0,x_1,\cdots,x_{n-1})\in W_n(k) :x_i\in m_k \bigr\} \\
W_n(m_k)^{(m)} = \Bigl\{X^{(n)}=(x_0,x_1,\cdots,x_{n-1})\in W_n(k): v(x_i)\geq m/p^{n-1-i} \Bigr \}
\end{empheq}
\end{document}
程序编译代码如下图
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